A charge q is placed at centre of line joining two equal charges Q . system of three charg

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1. Electric Charges and Fields

normal

A charge $q$ is placed at the centre of the line joining two equal charges $Q$. The system of the three charges will be in equilibrium, if $q$ is equal to

$-\frac{Q}{2}$

$-\frac{Q}{4}$

$+\frac{Q}{4}$

$+\frac{Q}{2}$

Solution

$\Rightarrow \frac{1}{4 \pi \varepsilon_{0}} \frac{\mathrm{Q}^{2}}{4 \mathrm{x}^{2}}=\frac{1}{4 \pi \varepsilon_{0}} \frac{\mathrm{qQ}}{\mathrm{x}^{2}} \Rightarrow \mathrm{q}=\frac{-\mathrm{Q}}{4}$

Standard 12

Physics

The force on a charge situated on the axis of a dipole is $F$. If the charge is shifted to double the distance, the new force will be

normal

A capacitor $C = 100$ $ \mu F$ is connected to three resistors each of resistance $1$ $kW$ and a battery of emf $9$ $V$. The switch $S $ has been closed for long time so as to charge the capacitor. When switch $S $ is opened, the capacitor discharges with time constant…..$ms$

normal

Charges $+q$ and $-q$ are placed at points $A$ and $B$ respectively which are at distance $2\,L$ apart, $C$ is the midpoint between $A$ and $B$ . The work done in moving a charge $+ Q$ along the semicircle $CRD$ is

normal

Calculate the work done in taking a charge $-2 \times 10^{-9} \,C$ from $A$ to $B$ via $C$ is ……… (in diagram)

normal

The equivalent capacitance between $A$ and $B$ is (in $\mu\, F$)

normal

A charge $q$ is placed at the centre of the line joining two equal charges $Q$. The system of the three charges will be in equilibrium, if $q$ is equal to

Solution

Similar Questions

The force on a charge situated on the axis of a dipole is $F$. If the charge is shifted to double the distance, the new force will be

A capacitor $C = 100$ $ \mu F$ is connected to three resistors each of resistance $1$ $kW$ and a battery of emf $9$ $V$. The switch $S $ has been closed for long time so as to charge the capacitor. When switch $S $ is opened, the capacitor discharges with time constant…..$ms$

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