Gujarati
Hindi
1. Electric Charges and Fields
normal

The force on a charge situated on the axis of a dipole is $F$. If the charge is shifted to double the distance, the new force will be

A

$4F$

B

$\frac{F}{2}$

C

$\frac{F}{4}$

D

$\frac{F}{8}$

Solution

$F = qE  \Rightarrow  F = q\frac{{2{K_p}}}{{{r^3}}}$

If distance doubled $\Rightarrow $ forces becomes $\frac{1}{8}^{th}$ 

Standard 12
Physics

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