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1. Electric Charges and Fields
normal
The force on a charge situated on the axis of a dipole is $F$. If the charge is shifted to double the distance, the new force will be
A
$4F$
B
$\frac{F}{2}$
C
$\frac{F}{4}$
D
$\frac{F}{8}$
Solution
$F = qE \Rightarrow F = q\frac{{2{K_p}}}{{{r^3}}}$
If distance doubled $\Rightarrow $ forces becomes $\frac{1}{8}^{th}$
Standard 12
Physics