Gujarati
Hindi
1. Electric Charges and Fields
normal

A charge $q$ is placed at the centre of cubical box of side a with top open. The flux of the electricn field through one of the surface of the cubical box is

A

zero

B

$q/{\varepsilon _0}$

C

$q/{6\varepsilon _0}$

D

$5q/{6\varepsilon _0}$

Solution

Total flux through cube $=\frac{q}{\varepsilon_{0}}$

Flux through each surface $=\frac{\mathrm{q}}{6 \varepsilon_{0}}$

Standard 12
Physics

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