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1. Electric Charges and Fields
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A charge $q$ is placed at the centre of cubical box of side a with top open. The flux of the electricn field through one of the surface of the cubical box is
A
zero
B
$q/{\varepsilon _0}$
C
$q/{6\varepsilon _0}$
D
$5q/{6\varepsilon _0}$
Solution

Total flux through cube $=\frac{q}{\varepsilon_{0}}$
Flux through each surface $=\frac{\mathrm{q}}{6 \varepsilon_{0}}$
Standard 12
Physics
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