Electric potential (V) as a function of distance (x) [in meters] is given by V = (5x^2 + 10 x -9), V

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1. Electric Charges and Fields

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The electric potential $(V)$ as a function of distance $(x)$ [in meters] is given by $V = (5x^2 + 10 x -9)\, Volt$. The value of electric field at $x = 1\, m$ would be......$Volt/m$

A

$20$

B

$6$

C

$11$

D

$-23$

Solution

$E=-\frac{d v}{d x}=-(10 x+10)$

$\mathrm{E}=-120$ $\mathrm{volt}/$ $\mathrm{m},$ at $\mathrm{x}=1 \mathrm{\,m}$

Standard 12

Physics

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