Gujarati
Hindi
1. Electric Charges and Fields
normal

A charge $2\,\mu C$ is taken from infinity to a point in an electric field, without changing its velocity. If work done against forces is $20\,\mu J$ then potential at that point will be.....$V$

A

$-20$

B

$10$

C

$-10$

D

$30$

Solution

$V = \frac{{{W_{ext}}}}{q} = \frac{{20\,\mu J}}{{2\,\mu C}} =  + 10\,V$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.