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1. Electric Charges and Fields
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A charge $2\,\mu C$ is taken from infinity to a point in an electric field, without changing its velocity. If work done against forces is $20\,\mu J$ then potential at that point will be.....$V$
A
$-20$
B
$10$
C
$-10$
D
$30$
Solution
$V = \frac{{{W_{ext}}}}{q} = \frac{{20\,\mu J}}{{2\,\mu C}} = + 10\,V$
Standard 12
Physics
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