Electric flux from a cube of edge l is phi . If an edge of cube is made 2l and charge enclosed is ha

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1. Electric Charges and Fields

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The electric flux from a cube of edge $l$ is $\phi $. If an edge of the cube is made $2l$ and the charge enclosed is halved, its value will be

A

$4\phi $

B

$2\phi $

C

$\frac{\phi }{2}$

D

$\phi $

Solution

$\phi = \frac{q}{{{\varepsilon _0}}}$ (independent of dimensions)

${\phi _2} = \frac{q}{{2{\varepsilon _0}}} = \frac{\phi }{2}$

Standard 12

Physics

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