A charge q is placed at centre of open end of cylindrical vessel. flux of electric field through sur

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1. Electric Charges and Fields

easy

A charge $q$ is placed at the centre of the open end of cylindrical vessel. The flux of the electric field through the surface of the vessel is

AZero

B$\frac{q}{{{\varepsilon _0}}}$

C$\frac{q}{{2{\varepsilon _0}}}$

D$\frac{{2q}}{{{\varepsilon _0}}}$

Solution

(c) To apply Gauss's theorem it is essential that charge should be placed inside a closed surface. So imagine another similar cylindrical vessel above it as shown in figure (dotted).

Standard 12

Physics

A hollow cylinder has a charge $q$ coulomb within it. If $\phi$ is the electric flux in units of $volt-meter$ associated with the curved surface $B,$ the flux linked with the plane surface $A$ in units of $V-m$ will be

medium

(AIPMT-2007)

Give reason : ''If net flux assocaited with closed surface is zero, then net charge enclosed by that surface is zero''.

medium

In figure a point charge $+Q_1$ is at the centre of an imaginary spherical surface and another point charge $+Q_2$ is outside it. Point $P$ is on the surface of the sphere. Let ${\Phi _s}$be the net electric flux through the sphere and ${\vec E_p}$ be the electric field at point $P$ on the sphere. Which of the following statements is $TRUE$ ?

medium

A cube of side $l$ is placed in a uniform field $E$, where $E = E\hat i$. The net electric flux through the cube is

easy

Draw electric field by negative charge.

easy

A charge $q$ is placed at the centre of the open end of cylindrical vessel. The flux of the electric field through the surface of the vessel is

Solution

Similar Questions

A hollow cylinder has a charge $q$ coulomb within it. If $\phi$ is the electric flux in units of $volt-meter$ associated with the curved surface $B,$ the flux linked with the plane surface $A$ in units of $V-m$ will be

Give reason : ''If net flux assocaited with closed surface is zero, then net charge enclosed by that surface is zero''.

A cube of side $l$ is placed in a uniform field $E$, where $E = E\hat i$. The net electric flux through the cube is

Draw electric field by negative charge.

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