A charge of 10 ,μ C is placed at origin of x-y coordinate system. potential difference between two

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2. Electric Potential and Capacitance

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A charge of $10 \,\mu C$ is placed at the origin of $x-y$ coordinate system. The potential difference between two points $(0, a)$ and $(a, 0)$ in volt will be

A

$\frac{9 \times 10^4}{a}$

B

$\frac{9 \times 10^4}{a \sqrt{2}}$

C

$\frac{9 \times 10^4}{2 a}$

D

$0$

Solution

(d)

$V_A=\frac{k q}{a}$

$V_B=\frac{k q}{a}$

$\Delta V=V_A-V_B=0$

Standard 12

Physics

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