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2. Electric Potential and Capacitance
medium
A charge of ${10^{ - 9}}\,C$ is placed on each of the $64$ identical drops of radius $2\,cm$. They are then combined to form a bigger drop. Find its potential
A
$7.2 \times {10^3}\,V$
B
$7.2 \times {10^2}\,V$
C
$1.44 \times {10^2}\,V$
D
$1.44 \times {10^3}\,V$
Solution
(a) $V = {n^{2/3}}v$ $==>$ $V = {(64)^{2/3}} \times 9 \times {10^9} \times \frac{{{{10}^{ – 9}}}}{{(2 \times {{10}^{ – 2}})}}$
= $7.2 \times {10^3}\,V$
Standard 12
Physics