A charge particle of charge $q$ and mass $m$ is accelerated through a potential diff. $V\, volts$. It enters a region of orthogonal magnetic field $B$. Then radius of its circular path will be
A charge particle of charge $q$ and mass $m$ is accelerated through a potential diff. $V\, volts$. It enters a region of orthogonal magnetic field $B$. Then radius of its circular path will be
- A
$\sqrt {\frac{{Vm}}{{2q{B^2}}}} $
- B
${\frac{{2Vm}}{{q{B^2}}}}$
- C
$\sqrt {\frac{{2Vm}}{q}} \left( {\frac{1}{B}} \right)$
- D
$\sqrt {\frac{{Vm}}{q}} \left( {\frac{1}{B}} \right)$
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