Gujarati
Hindi
4-1.Newton's Laws of Motion
normal

A child is standing at one end of a long trolley moving with a speed $v$ on a smooth horizontal floor. If the child starts running towards the other end of the trolley with a speed $u$ , the centre of mass of the system (trolley + child) will move with a speed

A

zero

B

$(v + u)$

C

$(v -u)$

D

$v$

Solution

The speed of the centre of mass of the system remains unchanged (equal to $v$ ) because no external froce acts on the system. The forces involved in running on the trolley are internal to this system

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.