A road is 10, m wide. Its radius of curvature is 50, m . outer edge is above lower edge by a distanc

English

Gujarati

Hindi

4-1.Newton's Laws of Motion

normal

A road is $10\, m$ wide. Its radius of curvature is $50\, m$. The outer edge is above the lower edge by a distance of $1.5\, m$. this road is most suited for the velocity ........ $m/s$

A

$2.5$

B

$4.5$

C

$6.5$

D

$8.5$

Solution

$\tan \theta=\frac{1.5}{10}=0.15$

$\tan \theta=\frac{\mathrm{v}^{2}}{\mathrm{rg}} \quad \Rightarrow \quad \mathrm{v}=\sqrt{\mathrm{rg} \tan \theta}$

$=\sqrt{50 \times 9.8 \times 0.15}=8 .57 \mathrm{m} / \mathrm{s}$

Standard 11

Physics

Share

Similar Questions

A particle of mass $m$, initially at rest, is acted on by a force $F = F_0 \left\{ {1 – {{\left( {\frac{{2t – T}}{T}} \right)}^2}} \right\}$ during the interval $0 \leq 0 \leq t \leq T$. The velocity of the particle at the end of the interval is :

normal

The $50\, kg$ homogeneous smooth sphere rests on the $30^o$ incline $A$ and bears against the smooth vertical wall $B$. Calculate the contact force at $A$

normal

A block of mass $M$ is pulled along a horizontal frictionless surface by a rope of mass $m$. If a force $P$ is applied at the free end of the rope, the force exerted by the rope on the block is-

normal

A player caught a cricket ball of mass $150\, gm$ moving at the rate of $20 \,m/sec$. if the catching process be completed in $ 0.1 \,sec$ the force of the blow exerted by the ball on the hands of player is ……….. $N$

easy

Choose the correct statement

normal