A coin is tossed twice, probability that atleast one tail occurs ?

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14.Probability

easy

A coin is tossed twice, what is the probability that atleast one tail occurs ?

A

$\frac{3}{4}$

B

$\frac{3}{4}$

C

$\frac{3}{4}$

D

$\frac{3}{4}$

Solution

When a coin is tossed twice, the sample space is given by

$S =\{ HH , HT , TH , TT \}$

Let $A$ be the event of the occurrence of the least one tail.

Accordingly, $A=\{H T, T H, T T\}$

$\therefore P ( A )=\frac{\text { Number of outcomes favourable to } A }{\text { Total number of possibe outcomes }}$

$=\frac{n(A)}{n(S)}$

$=\frac{3}{4}$

Standard 11

Mathematics

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