A committee of two persons is selected from two men and two women. What is the probability that the committee will have  two men ?

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The total number of persons $=2+2=4 .$ Out of these four person, two can be selected in $^{4} C _{2}$ ways.

Two men can be selected in $^{2} C _{2}$ way.

Hence $P$ (Two men) $=\frac{^{2} C _{2}}{^{4} C _{2}}$ $=\frac{1}{^{4} C _{2}}=\frac{1}{6}$

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