Gujarati
Hindi
2. Electric Potential and Capacitance
normal

A conducting sphere $A$ of radius $a$, with charge $Q$, is placed concentrically inside a conducting shell $B$ of radius $b$. $B$ is earthed. $C$ is the common centre of the $A$ and $B$. 

A

The field is a distance $r$ from $C$, where $a \leq  r \leq  b,$ is $\frac{1}{{4\pi \,{\varepsilon _0}}}\,\frac{Q}{{{r^2}}}$

B

The potential at a distance $r$ from $C$, where $a \leq  r \leq  b,$ $\frac{1}{{4\pi \,{\varepsilon _0}}}\,Q\,\left( {\frac{1}{r}\, - \,\frac{1}{b}} \right)$

C

The potential difference between $A$ and $B$ is $\frac{1}{{4\pi \,{\varepsilon _0}}}\,Q\,\left( {\frac{1}{a}\, - \,\frac{1}{b}} \right)$

D

all of the above

Solution

$a \leq r \leq b, E=k \frac{Q}{r^{2}}$

$V_{A}-V_{B}=\frac{1}{4 \pi \in_{0}}\left[\left\{\frac{Q}{a}+\frac{-Q}{b}\right\}-\left\{\frac{Q}{b}+\frac{-Q}{b}\right\}\right]$

$=\frac{1}{4 \pi \epsilon_{0}} Q\left[\frac{1}{a}-\frac{1}{b}\right]=k Q\left(\frac{1}{a}-\frac{1}{b}\right)$

$V=\frac{1}{4 \pi \in 0}\left[\frac{Q}{r}+\frac{-Q}{b}=k Q\left(\frac{1}{r}-\frac{1}{b}\right)\right.$

Standard 12
Physics

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