- Home
- Standard 12
- Physics
1. Electric Charges and Fields
easy
A conductor has $14.4 \times {10^{ - 19}}coulombs$ positive charge. The conductor has(Charge on electron $ = 1.6 \times {10^{ - 19}}coulombs$)
A
$9$ electrons in excess
B
$27$ electrons in short
C
$27$ electrons in excess
D
$9$ electrons in short
Solution
(d) Positive charge shows the deficiency of electrons. Number of electrons $ = \frac{{14.4 \times {{10}^{ – 19}}}}{{1.6 \times {{10}^{ – 19}}}} = 9$
Standard 12
Physics
