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4-1.Newton's Laws of Motion
normal
A constant force $F$ is applied in horizontal direction as shown. Contact force between $M$ and $m$ is $N$ and between $m$ and $M ^{\prime}$ is $N ^{\prime}$ then

A
$N$ or $N ^{\prime}$ equal
B
$N > N^{\prime}$
C
$N ^{\prime} > N$
D
cannot be determined
Solution

$F-N_1=M a$
$N_1-N_2=m a$
$N_2=M^{\prime} a$
$N_1=\left(M^{\prime}+m\right) a$
$\therefore M^{\prime} > M \quad \Rightarrow N_1 > N_2$
Standard 11
Physics