Gujarati
Hindi
4-1.Newton's Laws of Motion
normal

A constant force $F$ is applied in horizontal direction as shown. Contact force between $M$ and $m$ is $N$ and between $m$ and $M ^{\prime}$ is $N ^{\prime}$ then

A

$N$ or $N ^{\prime}$ equal

B

$N > N^{\prime}$

C

$N ^{\prime} > N$

D

cannot be determined

Solution

$F-N_1=M a$

$N_1-N_2=m a$

$N_2=M^{\prime} a$

$N_1=\left(M^{\prime}+m\right) a$

$\therefore M^{\prime} > M \quad \Rightarrow N_1 > N_2$

Standard 11
Physics

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