- Home
- Standard 11
- Physics
4-1.Newton's Laws of Motion
normal
A mass $M$ is suspended by a rope from a rigid support at $A$ as shown in figure. Another rope is tied at the end $B$, and it is pulled horizontally with a force $.......$ with the vertical in equilibrium, then the tension in the string $AB$ is :

A
$F / \sin \theta$
B
$F \sin \theta$
C
$F \cos \theta$
D
$F / \cos \theta$
Solution

$T \sin \theta= F$
$T=\frac{F}{\sin \theta}$
Standard 11
Physics
Similar Questions
hard
normal