Gujarati
Hindi
4-1.Newton's Laws of Motion
normal

A mass $M$ is suspended by a rope from a rigid support at $A$ as shown in figure. Another rope is tied at the end $B$, and it is pulled horizontally with a force $.......$ with the vertical in equilibrium, then the tension in the string $AB$ is :

A

$F / \sin \theta$

B

$F  \sin \theta$

C

$F  \cos \theta$

D

$F / \cos \theta$

Solution

$T \sin \theta= F$

$T=\frac{F}{\sin \theta}$

Standard 11
Physics

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