A cricket player catches a ball of mass 120 mathrm{~g} moving with 25 mathrm{~m} / mathrm{s} speed.

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4-1.Newton's Laws of Motion

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A cricket player catches a ball of mass $120 \mathrm{~g}$ moving with $25 \mathrm{~m} / \mathrm{s}$ speed. If the catching process is completed in $0.1 \mathrm{~s}$ then the magnitude of force exerted by the ball on the hand of player will be (in SI unit):

A

$24$

B

$12$

C

$25$

D

$30$

(JEE MAIN-2024)

Solution

$\mathrm{F}_{\mathrm{ar}}=\frac{\Delta \mathrm{p}}{\Delta \mathrm{t}}$

$=\frac{0.12 \times 25}{0.1}=30 \mathrm{~N}$

Standard 11

Physics

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