A cricket ball of mass 250, g collides with a bat with velocity 10 ,m/s and returns with same veloci

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4-1.Newton's Laws of Motion

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A cricket ball of mass $250\, g$ collides with a bat with velocity $10 \,m/s$ and returns with the same velocity within $0.01 \,second$. The force acted on bat is ....... $N$

A

$25$

B

$50$

C

$250$

D

$500$

Solution

(d)Force$ = m\;\left( {\frac{{dv}}{{dt}}} \right) = \frac{{0.25 \times [(10) – ( – 10)]}}{{0.01}} = 25 \times 20 = 500\;N$

Standard 11

Physics

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