A cubical block of wood of edge $10$ $cm$ and mass $0.92$ $kg$ floats on a tank of water with oil of rel. density $0.6$ to a depth of $4$ $cm$ above water. When the block attains equilibrium with four of its sides edges vertical
$1$ $cm$ of it will be above the free surface of oil.
$8 $ $cm$ of it will be under water.
$2$ $cm$ of it will be above the common surface of oil and water.
$B$ and $C$ both
A solid sphere of radius $r$ is floating at the interface of two immiscible liquids of densities $\rho_1$ and $\rho_2\,\, (\rho_2 > \rho_1),$ half of its volume lying in each. The height of the upper liquid column from the interface of the two liquids is $h.$ The force exerted on the sphere by the upper liquid is $($ atmospheric pressure $= p_0\,\,\&$ acceleration due to gravity is $g) $
A cubical block is floating in a liquid with half of its volume immersed in the liquid. When the whole system accelerates upwards with acceleration of $g/3,$ the fraction of volume immersed in the liquid will be
A person is sitting in a boat floating in a lake. This person fills a bucket of water from lake and puts in the boat, then will the water level go down in the lake ? Explain.
A body floats in a liquid contained in a beaker. The whole system as shown falls freely under gravity. The upthrust on the body due to the liquid is
A cube of wood supporting $200\,gm$ mass just floats in water. When the mass is removed, the cube rises by $2\, cm$. ............ $cm$ is the side of cube .