A fluid container is containing a liquid of density $\rho $ is accelerating upward with acceleration a along the inclined place of inclination $\alpha$ as shown. Then the angle of inclination $ \theta $ of free surface is :
A fluid container is containing a liquid of density $\rho $ is accelerating upward with acceleration a along the inclined place of inclination $\alpha$ as shown. Then the angle of inclination $ \theta $ of free surface is :
- A
${\tan ^{ - 1}}\left[ {\frac{a}{{g\cos \alpha }}} \right]$
- B
${\tan ^{ - 1}}\left[ {\frac{{a + g\sin \alpha }}{{g\cos \alpha }}} \right]$
- C
${\tan ^{ - 1}}\left[ {\frac{{a - g\sin \alpha }}{{g(1 + \cos \alpha )}}} \right]$
- D
${\tan ^{ - 1}}\left[ {\frac{{a - g\sin \alpha }}{{g(1 - \cos \alpha )}}} \right]$
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- [AIIMS 2014]
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