A cyclist starts from centre 0 of a circular park of radius $1\, km$ and, moves along the path $OPRQO$ as shown in figure.
If he maintains constant speed of $10\, ms^{-1}$, what is his acceleration at point $R$ in magnitude and direction ?
A cyclist starts from centre 0 of a circular park of radius $1\, km$ and, moves along the path $OPRQO$ as shown in figure.
If he maintains constant speed of $10\, ms^{-1}$, what is his acceleration at point $R$ in magnitude and direction ?
Here, object performs circular motion. Hence, its acceleration is called centripetal acceleration.
Hence, acceleration at $\mathrm{R}$ is,
$a=\frac{v^{2}}{r}=\frac{(10)^{2}}{1 \mathrm{~km}}=\frac{100}{10^{3}}$
$=0.1 \mathrm{~m} / \mathrm{s}^{2}$ along $\mathrm{RO}$ (towards centre)
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