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1. Electric Charges and Fields
easy
A cylinder of radius $R$ and length $L$ is placed in a uniform electric field $E$ parallel to the cylinder axis. The total flux for the surface of the cylinder is given by
A
$2\pi {R^2}E$
B
$\pi {R^2}/E$
C
$(\pi {R^2} - \pi R)/E$
D
Zero
Solution
(d) Flux through surface $A \,{\varphi _A} = E \times \pi {R^2}$ and ${\varphi _B} = – E \times \pi {R^2}$
Flux through curved surface C $ = \int {\overrightarrow E .\overrightarrow {ds} } = \int {E\,ds\cos {{90}^o}} = 0$
Total flux through cylinder $ = {\varphi _A} + {\varphi _B} + {\varphi _C}= 0$
Standard 12
Physics
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