A cylindrical vessel filled with water upto height H becomes empty in time t_0 due to a small hole a

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9-1.Fluid Mechanics

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A cylindrical vessel filled with water upto the height $H$ becomes empty in time $t_0$ due to a small hole at the bottom of the vessel. If water is filled to a height $4H$ it will flow out in time

A

$t_0$

B

$4t_0$

C

$8t_0$

D

$2t_0$

Solution

$v -u=-g t$

$u =\sqrt{2 g h}$

$t =\sqrt{\frac{2 g}{h}}$

$\frac{t_1}{t_2}=\sqrt{\frac{h_1}{h_2}}=\sqrt{\frac{h}{4 h}}$

$\therefore t_2=2 t_0$

Standard 11

Physics

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