A direct current of 5,A is superposed on an a | vedclass

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Question

(b)

Total carrent, $I =(5+10 \sin \omega t )$

$\Rightarrow \quad I _{ eff }=\left[\frac{\int \limits_0^{ T } I ^2 dt }{\int \limits_0^{ T } dt }

Vedclass · Accepted Answer

$5 \sqrt{3}\,A$

Vedclass · Answer

(b)

Total carrent, $I =(5+10 \sin \omega t )$

$\Rightarrow \quad I _{ eff }=\left[\frac{\int \limits_0^{ T } I ^2 dt }{\int \limits_0^{ T } dt }ight]^{1 / 2}$

$=\left[\frac{1}{ T } \int \limits _0^{ T }(5+10 \sin \omega t)^2 dt ight]^{1 / 2}$

$\frac{1}{ T } \int \limits _0^{ T } \sin ^2 \omega t . d t=\frac{1}{2}$

So, $I _{ eff }=\left[25+\frac{1}{2} 	imes 100ight]^{1 / 2}=5 \sqrt{3} A$

A direct current of $5\,A$ is superposed on an alternating current $I =10 \sin \omega t$ flowing through the wire. The effective value of the resulting current will be

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