The peak voltage of the ac source is equal to:
the $rms$ value of the ac source
$\sqrt{2}$ times the $rms$ value of the $ac$ source
$\frac{1}{\sqrt{2}}$ times the $rms$ value of the $ac$ source
the value of voltage supplied to the circuit
The ratio of peak value and r.m.s value of an alternating current is
The maximum value of $a.c.$ voltage in a circuit is $707V$. Its rms value is.....$V$
An alternating voltage is given by : $e = e_1\, \sin \omega t + e_2\, \cos \omega t$. Then the root mean square value of voltage is given by :-
In $ac$ circuit when $ac$ ammeter is connected it reads $i$ current if a student uses $dc$ ammeter in place of $ac$ ammeter the reading in the $dc$ ammeter will be:
The voltage of $AC$ source varies with time according to the equation, $V = 100\, \sin 100\, \pi \, t \, \cos \,100\, \pi \,t$. Where $t$ is in second and $V$ is in volt. Then:-