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6.Permutation and Combination
medium
A father with $8$ children takes them $3$ at a time to the Zoological gardens, as often as he can without taking the same $3$ children together more than once. The number of times each child will go to the garden is
A
$56$
B
$21$
C
$112$
D
None of these
Solution
(b) Each child will go as often as he (or she) can be accompanied by two others.
Therefore the required number is ${^7}{C_2} = 21$.
Standard 11
Mathematics