A force acts on a $3\, gm$ particle in such a way that the position of the particle as a function of time is given by $x = 3t -4t^2 + t^3$ , where $x$ is in $meters$ and $t$ is in $seconds$ . The work done during the first $4\, second$ is ................. $\mathrm{mJ}$

  • A

    $384$

  • B

    $168$

  • C

    $528$

  • D

    $541$

Similar Questions

Work done by the frictional force is

A body of mass $m$ is moving in a circle of radius $r$ with a constant speed $v$. The force on the body is $\frac{mv^2}{r}$ and is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle

A sphere of mass $m$ travelling at constant speed $v$ strike another sphere of same mass. If  coefficient of restitution is $e$, then ratio of velocity of both spheres just after collision is :-

A cord is used to lower vertically a block of mass $M$ by a distance $d$ with constant downward acceleration $\frac{g}{4}$. Work done by the cord on the block is

Two identical particles are moving with same velocity $v$ as shown in figure. If the  collision is completely inelastic then