A force of 5, N acts on a particle along a direction making an angle of 60^° with vertical. Its

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3-1.Vectors

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A force of $5\, N$acts on a particle along a direction making an angle of $60^°$ with vertical. Its vertical component be.......$N$

A$10$

B$3$

C$4$

D$2.5$

Solution

(d)The component of force in vertical direction =$F\cos \theta $
$= F\cos 60^\circ $ $ = 5 \times \frac{1}{2}\,\, = 2.5\,N$

Standard 11

Physics

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