Given vector overrightarrow A = 2hat i + 3hat | vedclass

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Question

(b) $\vec{A}=2 \hat{i}+3 \hat{j}$

$A=|\vec{A}|=\sqrt{4+9}=\sqrt{13}$

$\cos \beta=\frac{y}{A}=\frac{3}{\sqrt{13}}$

$\cos \beta=\frac{3}{\sqrt{

Vedclass · Accepted Answer

${	an ^{ - 1}}2/3$

Vedclass · Answer

(b) $\vec{A}=2 \hat{i}+3 \hat{j}$

$A=|\vec{A}|=\sqrt{4+9}=\sqrt{13}$

$\cos \beta=\frac{y}{A}=\frac{3}{\sqrt{13}}$

$\cos \beta=\frac{3}{\sqrt{13}}$

$\sin \beta=\frac{x}{A}=\frac{2}{\sqrt{13}}$

$\operatorname{Tan} \beta =\frac{x}{y}=\frac{2}{3}$

$=	an ^{-1}\left(\frac{2}{3}ight)$

Given vector $\overrightarrow A = 2\hat i + 3\hat j, $ the angle between $\overrightarrow A $and $y-$axis is

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