A frog hops along a straight line path from point 'A^{prime} to point { }^{prime} B ^{prime} in

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7. MOTION

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A frog hops along a straight line path from point $'A^{\prime}$ to point ${ }^{\prime} B ^{\prime}$ in $10\, s$ and then turns and hops to point ${ }^{\prime} C^{\prime}$ in another $5\, s$. Calculate the average speed and average velocity of the frog for the motion between $(a)(A)$ to $(B)(b)(A)$ to $(C)($ through $B)$

Option A

Option B

Option C

Option D

Solution

For $A$ to $B$, we have

Average speed $=$ Average velocity

$=\frac{(7-(-2))}{10}=0.9 m s ^{-1}$

For $A$ to $C$ through $B$, we have Average speed $=\frac{(7-(-2)+3-(-2))}{15}=\frac{14}{15} m s ^{-1}$

Average velocity $=\frac{(7-(3))}{15}=\frac{4}{15} m s ^{-1}$

Standard 9

Science

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