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7. MOTION
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A frog hops along a straight line path from point $'A^{\prime}$ to point ${ }^{\prime} B ^{\prime}$ in $10\, s$ and then turns and hops to point ${ }^{\prime} C^{\prime}$ in another $5\, s$. Calculate the average speed and average velocity of the frog for the motion between $(a)(A)$ to $(B)(b)(A)$ to $(C)($ through $B)$

Option A
Option B
Option C
Option D
Solution
For $A$ to $B$, we have
Average speed $=$ Average velocity
$=\frac{(7-(-2))}{10}=0.9 m s ^{-1}$
For $A$ to $C$ through $B$, we have Average speed $=\frac{(7-(-2)+3-(-2))}{15}=\frac{14}{15} m s ^{-1}$
Average velocity $=\frac{(7-(3))}{15}=\frac{4}{15} m s ^{-1}$
Standard 9
Science
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