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4-1.Newton's Laws of Motion
easy
A gun fires a bullet of mass $50 \,gm$ with a velocity of $30\,m\,{\sec ^{ - 1}}$. Because of this the gun is pushed back with a velocity of $1\,m\,{\sec ^{ - 1}}$. The mass of the gun is .......... $kg$
A
$15$
B
$30$
C
$1.5 $
D
$20$
(AIIMS-2001)
Solution
(c)${m_G} = \frac{{{m_B}{v_B}}}{{{v_G}}}$$\frac{{50 \times {{10}^{ – 3}} \times 30}}{1} = 1.5\;kg$
Standard 11
Physics
