Gujarati
Hindi
4-1.Newton's Laws of Motion
medium

A stationary body of mass $m$ gets exploded in $3$ parts having mass in the ratio of $1 : 3 : 3$. Its two fractions having equal mass moving at right angle to each other with velocity of $15\,m/sec$. Then the velocity of the third body is

A

$42\sqrt {(2)}\,m/sec$

B

$5\,m/sec$

C

$5\sqrt {(32)}\,m/sec$

D

none of these

Solution

$\mathrm{mv}=\sqrt{(3 \mathrm{m} \times 15)^{2}+(3 \mathrm{m} \times 15)^{2}}$

$\mathrm{mv}=45 \mathrm{m} \sqrt{2}$

$\mathrm{v}=45 \sqrt{2} \mathrm{m} / \mathrm{s}$

Standard 11
Physics

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