4-1.Newton's Laws of Motion
easy

A gun of mass $10 \,kg$ fires $4$ bullets per second. The mass of each bullet is $20 \,g$ and the velocity of the bullet when it leaves the gun is $300\, m / s$. The force required to hold the gun while firing is (in $N$)

A

$6$

B

$8$

C

$24$

D

$240$

(AIIMS-2019) (AIIMS-2016)

Solution

The rate of change of momentum of the bullet in the forward direction is,

$\frac{d p}{d t}=F=n m v$

$=4 \times 20 \times 10^{-3} \times 300$

$=24 N$

Standard 11
Physics

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