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4-1.Newton's Laws of Motion
easy
A gun of mass $10 \,kg$ fires $4$ bullets per second. The mass of each bullet is $20 \,g$ and the velocity of the bullet when it leaves the gun is $300\, m / s$. The force required to hold the gun while firing is (in $N$)
A
$6$
B
$8$
C
$24$
D
$240$
(AIIMS-2019) (AIIMS-2016)
Solution
The rate of change of momentum of the bullet in the forward direction is,
$\frac{d p}{d t}=F=n m v$
$=4 \times 20 \times 10^{-3} \times 300$
$=24 N$
Standard 11
Physics