A hole is drilled in a copper sheet. The diameter of the hole is $4.24\; cm$ at $27.0\,^{\circ} C$ What is the change in the diameter of the hole when the sheet is heated to $227\,^{\circ} C ?$ Coefficient of linear expansion of copper $=1.70 \times 10^{-5}\; K ^{-1}$
A hole is drilled in a copper sheet. The diameter of the hole is $4.24\; cm$ at $27.0\,^{\circ} C$ What is the change in the diameter of the hole when the sheet is heated to $227\,^{\circ} C ?$ Coefficient of linear expansion of copper $=1.70 \times 10^{-5}\; K ^{-1}$
Initial temperature, $T_{1}=27.0^{\circ} C$
Diameter of the hole at $T_{1}, d_{1}=4.24 cm$
Final temperature, $T_{2}=227^{\circ} C$
Diameter of the hole at $T_{2}=d_{2}$
Co-efficient of linear expansion of copper, $\alpha cu =1.70 \times 10^{-5} K ^{-1}$
For co-efficient of superficial expansion $\beta$, and change in temperature $\Delta T$, we have the relation:
$\frac{\text { Change in area }(\Delta A)}{\text { Original area }(A)}=\beta \Delta T$
$\frac{\left(\pi \frac{d_{2}^{2}}{4}-\pi \frac{d_{1}^{2}}{4}\right)}{\left(\pi \frac{d_{1}^{2}}{4}\right)}=\frac{\Delta A}{A}$
$\therefore \frac{\Delta A}{A}=\frac{d_{2}^{2}-d_{1}^{2}}{d_{1}^{2}}$
But $\beta=2 \alpha$
$\therefore \frac{d_{2}^{2}-d_{1}^{2}}{d_{1}^{2}}=2 \alpha \Delta T$
$\frac{d_{2}^{2}}{d_{1}^{2}}-1=2 \alpha\left(T_{2}-T_{1}\right)$
$\frac{d_{2}^{2}}{(4.24)^{2}}=2 \times 1.7 \times 10^{-5}(227-27)+1$
$d_{2}^{2}=17.98 \times 1.0068=18.1$
$\therefore d_{2}=4.2544 cm$
Change in diameter $=d_{2}-d_{1}=4.2544-4.24=0.0144 cm$
Hence, the diameter increases by $1.44 \times 10^{-2}\; cm .$
Similar Questions
A bakelite beaker has volume capacity of $500\, cc$ at $30^{\circ} C$. When it is partially filled with $V _{ m }$ volume (at $30^{\circ}$ ) of mercury, it is found that the unfilled volume of the beaker remains constant as temperature is varied. If $\gamma_{\text {(beaker) }}=6 \times 10^{-6}{ }^{\circ} C ^{-1}$ and $\gamma_{(\text {mercury })}=1.5 \times 10^{-4}{ }^{\circ} C ^{-1},$ where $\gamma$ is the coefficient of volume expansion, then $V _{ m }($in $cc )$ is close to
A bakelite beaker has volume capacity of $500\, cc$ at $30^{\circ} C$. When it is partially filled with $V _{ m }$ volume (at $30^{\circ}$ ) of mercury, it is found that the unfilled volume of the beaker remains constant as temperature is varied. If $\gamma_{\text {(beaker) }}=6 \times 10^{-6}{ }^{\circ} C ^{-1}$ and $\gamma_{(\text {mercury })}=1.5 \times 10^{-4}{ }^{\circ} C ^{-1},$ where $\gamma$ is the coefficient of volume expansion, then $V _{ m }($in $cc )$ is close to
- [JEE MAIN 2020]
The pressure $( P )$ and temperature $( T )$ relationship of an ideal gas obeys the equation $PT ^2=$ constant. The volume expansion coefficient of the gas will be:
The pressure $( P )$ and temperature $( T )$ relationship of an ideal gas obeys the equation $PT ^2=$ constant. The volume expansion coefficient of the gas will be:
- [JEE MAIN 2023]
A metal rod of Young's modulus $Y$ and coefficient of thermal expansion $\alpha$ is held at its two ends such that its length remains invariant. If its temperature is raised by $t^{\circ} C$, the linear stress developed in it is
A metal rod of Young's modulus $Y$ and coefficient of thermal expansion $\alpha$ is held at its two ends such that its length remains invariant. If its temperature is raised by $t^{\circ} C$, the linear stress developed in it is
- [AIEEE 2011]
Coefficient of linear expansion of brass and steel rods are $\alpha_1$ and $\alpha_2$. Lengths of brass and steel rods are $l_1$ and $l_2$ respectively. If $\left(l_2-l_1\right)$ is maintained same at all temperatures, which one of the following relations holds good?
Coefficient of linear expansion of brass and steel rods are $\alpha_1$ and $\alpha_2$. Lengths of brass and steel rods are $l_1$ and $l_2$ respectively. If $\left(l_2-l_1\right)$ is maintained same at all temperatures, which one of the following relations holds good?
- [NEET 2016]
The loss in weight of a solid when immersed in a liquid at $0^o C$ is $W_0$ and at $t^o C$ is $W$. If cubical coefficient of expansion of the solid and the liquid by $\gamma_s$ and $\gamma_l$ respectively, then $W$ is equal to :
The loss in weight of a solid when immersed in a liquid at $0^o C$ is $W_0$ and at $t^o C$ is $W$. If cubical coefficient of expansion of the solid and the liquid by $\gamma_s$ and $\gamma_l$ respectively, then $W$ is equal to :