4-2.Friction
easy

A lift is moving downwards with an acceleration equal to acceleration due to gravity. A body of mass $m$ kept on the floor of the lift is pulled horizontally. If the coefficient of friction is $\,\mu $, then the frictional resistance offered by the body is

A$mg$
B$\mu mg$
C$2\mu mg$
DZero

Solution

(d) $(N=\text { normal, } m=\text { mass of object, } a=$ acceleration of lift)
$m g-N=m a$
$N=m a-m g$
$(\text { given } a=g)$
therefore $N=0$
friction $=u . N$
hence friction $=u .0(\mathrm{N}=0)$
$=0$
Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.