When F = 2N , frictional force between 5 kg block and ground is ...... N

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4-2.Friction

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When $F = 2N$, the frictional force between $5 kg$ block and ground is ...... $N$

A

$2$

B

$0$

C

$8 $

D

$10 $

Solution

$\mathrm{F}_{1} \mathrm{max}=0.1 \times 10 \times 10=10 \mathrm{N}$

$\mathrm{F}_{2} \max =0.3 \times 15 \times 10=45 \mathrm{N}$

For $\mathrm{F}=2 \mathrm{N},$ static friction come in to play at both surfaces.

$\therefore F=F_{2}$

$\therefore F_{2}=2 N$

Standard 11

Physics

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