A light string passing over a smooth light fixed pulley connects two blocks of masses $m_1$ and $m_2$. If the acceleration of the system is $g / 8$, then the ratio of masses is
$\frac{9}{7}$
$\frac{8}{1}$
$\frac{4}{3}$
$\frac{5}{3}$
The end $B$ of the rod $AB$ which makes angle $\theta$ with the floor is being pulled with, a constant velocity $v_0$ as shown. The length of the rod is $l.$ At the instant when $\theta = 37^o $ then
In the adjoining figure if acceleration of $M$ with respect to ground is $a$, then
A uniform metal chain of mass $m$ and length ' $L$ ' passes over a massless and frictionless pulley. It is released from rest with a part of its length ' $l$ ' is hanging on one side and rest of its length ' $L -l$ ' is hanging on the other side of the pulley. At a certain point of time, when $l=\frac{L}{x}$, the acceleration of the chain is $\frac{g}{2}$. The value of $x$ is ........
Two particles $A$ and $B$ are connected by rigid rod $A B$. The rod slides along perpendicular rails as shown here. The velocity of $A$ to the left is $10\; m / s$. What is the velocity of $B$(in $m/s$) when angle $\alpha=60^{\circ}$?
The velocity of end ' $A$ ' of rigid rod placed between two smooth vertical walls moves with velocity ' $u$ ' along vertical direction. Find out the velocity of end ' $B$ ' of that rod, rod always remains in constant with the vertical walls.