A truck of mass $M$ is at rest on frictionless road when a monkey of mass $m$ starts moving on the truck in forward direction.If the truck recoils with a speed $v$ backward on the road, with what velocity is the monkey moving with respect to truck ?
$\left( {1 + \frac{m}{M}} \right)\,v$
$\left( {1 + \frac{M}{m}} \right)\,v$
$\frac{{mV}}{{(M + m)}}$
$\frac{{MV}}{{(m + M)}}$
The pulleys in the diagram are all smooth and light. The acceleration of $A$ is a upwards and the acceleration of $C$ is $f$ downwards. The acceleration of $B$ is
For the given fig. find the speed of block $A$ when $\theta = {60^o}$
In the system shown in figure pulleys and strings are ideal. Acceleration of $m_1\ w.r.t.\ m_2$ is $(m_1 = 2\ kg\ ; m_2 = 2\ kg)$
For the given diagram when block $B$ is pulled with velocity $V$ then velocity of block $A$ will be :-
In the arrangement shown in fig. the ends $P$ and $Q$ of an unstretchable string move downwards with uniform speed $U$. Pulleys $A$ and $B$ are fixed. Mass $M$ moves upwards with a speed.