11.Thermodynamics
medium

A litre of dry air at $STP$ expands adiabatically to a volume of $3$ litres. If $\gamma=1.40,$ the work done by air is$(3^{1.4}=4.6555)$ [Take air to be an ideal gas $]$

A

$90.5 \;J$

B

$48 \;J$

C

$60.7 \;J$

D

$100.8 \;J$

(JEE MAIN-2020)

Solution

$\mathrm{W}=\frac{\mathrm{nR}\left(\mathrm{T}_{1}-\mathrm{T}_{2}\right)}{\gamma-1}=\frac{\mathrm{P}_{1} \mathrm{V}_{1}-\mathrm{P}_{2} \mathrm{V}_{2}}{0.4}$

$W=\frac{100-\frac{100}{4.6555} \times 3}{0.4}=88.90\;J$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.