A litre of solution is saturated with AgCl . To this solution if 1.0 × {10^{ - 4}} mole of solid Na

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6-2.Equilibrium-II (Ionic Equilibrium)

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A litre of solution is saturated with $AgCl$. To this solution if $1.0 \times {10^{ - 4}}$ mole of solid $NaCl$ is added, what will be the $[A{g^ + }]$, assuming no volume change

A

More

B

Less

C

Equal

D

Zero

Solution

(b) $AgCl \to \mathop {A{g^ + }}\limits_x + \mathop {C{l^ – }}\limits_x $

After $NaCl $ is added $x + 1 \times {10^{ – 4}}$

That is why $A{g^ + }$ will be less.

Standard 11

Chemistry

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