Gujarati
Hindi
5.Work, Energy, Power and Collision
normal

A long spring, when stretched by a distance $x,$ has the potential energy $u.$ On increasing the stretching to $nx.$ The potential energy of the spring will be

A

$\frac {u}{n}$

B

$nu$

C

$n^2u$

D

$\frac {u}{n^2}$

Solution

$U{\kern 1pt}  = \,\frac{1}{2}\,K{x^2}\,\, \Rightarrow \,U\, \propto \,{x^2}$

Standard 11
Physics

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