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5.Magnetism and Matter
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A magnetic needle of negligible breadth and thickness compared to its length, oscillates in a horizontal plane with a period $T$. The period of oscillation of each part obtained on breaking the magnet into $n$ equal parts perpendicular to the length is
A
$T/n$
B
$T$
C
$T n$
D
$1/Tn$
Solution
(a)
$T=2 \pi \sqrt{\frac{I}{M B}}$
$T^{\prime}=2 \pi \sqrt{\frac{I}{n^3 \frac{M}{n} B}}=\frac{2 \pi}{n} \sqrt{\frac{I}{M B}}$
$T^{\prime}=\frac{T}{n}$
Standard 12
Physics