5.Magnetism and Matter
medium

A magnetic needle of negligible breadth and thickness compared to its length, oscillates in a horizontal plane with a period $T$. The period of oscillation of each part obtained on breaking the magnet into $n$ equal parts perpendicular to the length is

A

$T/n$

B

$T$

C

$T n$

D

$1/Tn$

Solution

(a)

$T=2 \pi \sqrt{\frac{I}{M B}}$

$T^{\prime}=2 \pi \sqrt{\frac{I}{n^3 \frac{M}{n} B}}=\frac{2 \pi}{n} \sqrt{\frac{I}{M B}}$

$T^{\prime}=\frac{T}{n}$

Standard 12
Physics

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