A man fires a bullet standing between two cliffs. First echo is heard after 3, seconds and second ec

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14.Waves and Sound

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A man fires a bullet standing between two cliffs. First echo is heard after $3\, seconds$ and second echo is heard after $5\, seconds$. If the velocity of sound is $330\,m/s$, then the distance between the cliffs is .... $m$

A

$1650$

B

$1320$

C

$990$

D

$660$

Solution

$2\left(d_{1}+d_{2}\right)=v\left(t_{1}+t_{2}\right)$

$\Rightarrow d_{1}+d_{2}=\frac{330 \times(3+5)}{2}=1320 \mathrm{\,m}$

Standard 11

Physics

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