Three blocks, A, B and C, of masses 4,kg, 2,k | vedclass

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Question

Here, $F=14 N$

$m_{A}=4 k g, m_{B}=2 k g, m_{C}=1 k g$

Total mass $m=m_{A}+m_{B}+m_{C}$

$=4+2+1=7 k g$

Acceleration of the system

$a=\f

Vedclass · Accepted Answer

$6$

Vedclass · Answer

Here, $F=14 N$

$m_{A}=4 k g, m_{B}=2 k g, m_{C}=1 k g$

Total mass $m=m_{A}+m_{B}+m_{C}$

$=4+2+1=7 k g$

Acceleration of the system

$a=\frac{F}{m}=\frac{14}{7}=2 m / s^{2}$

The contact force between $4 k g$ and $1 k g$ block with the same acceleration Let

$F_{1}$ be the contactv force

$	herefore F_{1}=\left(m_{B}+m_{C}ight) a=(2+1)=6 N$

Three blocks, $A, B$ and $C,$ of masses $4\,kg, 2\,kg$ and $1\,kg$ respectively, are in contact on a frictionless surface, as shown. If a force of $14\,\,N$ is applied on the $4\,\,kg$ block, then the contact force between $A$ and $B$ is ....... $N$

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