3.Current Electricity
easy

A meter bridge is set up as shown, to determine an unknown resistance ' $X$ ' using a standard $10\,ohm$ resistor. The galvanometer shows null point when tapping-key is at $52\,cm$ mark. The endcorrections are $1\,cm$ and $2\,cm$ respectively for the ends $A$ and $B$. The determined value of ' $X$ ' is $..........\Omega$

A

$10.2$

B

$10.6$

C

$10.8$

D

$11.1$

Solution

$b$

At Null point $\frac{X}{\ell_1}=\frac{10}{\ell_2} \Rightarrow$

$\frac{X}{53}=\frac{10}{50} \quad \therefore X=\frac{53}{5}=10.6 \Omega$

Standard 12
Physics

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