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3.Current Electricity
easy
A meter bridge is set up as shown, to determine an unknown resistance ' $X$ ' using a standard $10\,ohm$ resistor. The galvanometer shows null point when tapping-key is at $52\,cm$ mark. The endcorrections are $1\,cm$ and $2\,cm$ respectively for the ends $A$ and $B$. The determined value of ' $X$ ' is $..........\Omega$

A
$10.2$
B
$10.6$
C
$10.8$
D
$11.1$
Solution
$b$
At Null point $\frac{X}{\ell_1}=\frac{10}{\ell_2} \Rightarrow$
$\frac{X}{53}=\frac{10}{50} \quad \therefore X=\frac{53}{5}=10.6 \Omega$
Standard 12
Physics
Similar Questions
A student obtained following observations in an experiment of meter bridge to find the unknown resistance of the circuit The most accurate value of unknown resistance is ………… $\Omega$
S.No. | $R$ | $l$ | $100-l$ | $S = \left( {\frac{{100 – l}}{l}} \right)R$ |
$1$ | $20\,\Omega $ | $43$ | $57$ | $26.51\,\Omega $ |
$2$ | $30\,\Omega $ | $51$ | $49$ | $28.82\,\Omega $ |
$3$ | $40\,\Omega $ | $59$ | $41$ | $27.80\,\Omega $ |
$4$ | $60\,\Omega $ | $70$ | $30$ | $25.71\,\Omega $ |
medium