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12.Kinetic Theory of Gases
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A mixture of $2$ moles of helium gas (atomic mass $=$ $4$ $amu$) and $1$ $mole$ of argon gas (atomic mass $=$ $40$ $amu$) is kept at $300$ $K$ in a container. The ratio of the rms speeds $(\frac{V_{rms}(helium)}{V_{rms}(argon)})$ is
A
$0.32$
B
$0.45$
C
$2.24$
D
$3.16$
Solution
$v_{rms}=\sqrt{\frac{3 R T}{M}}$
$\Rightarrow \frac{\left(v_{rms}\right)_{H_{e}}}{\left(v_{-rms}\right)_{Ar}}=\sqrt{\frac{M_{A r}}{M_{H_{e}}}}=\sqrt{\frac{40}{4}}=\sqrt{10}=3.16$
Standard 11
Physics
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