Gujarati
Hindi
12.Kinetic Theory of Gases
normal

A mixture of $2$ moles of helium gas (atomic mass $=$ $4$ $amu$) and $1$ $mole$ of argon gas (atomic mass $=$ $40$ $amu$) is kept at $300$ $K$ in a container. The ratio of the rms speeds $(\frac{V_{rms}(helium)}{V_{rms}(argon)})$ is

A

$0.32$

B

$0.45$

C

$2.24$

D

$3.16$

Solution

$v_{rms}=\sqrt{\frac{3 R T}{M}}$

$\Rightarrow \frac{\left(v_{rms}\right)_{H_{e}}}{\left(v_{-rms}\right)_{Ar}}=\sqrt{\frac{M_{A r}}{M_{H_{e}}}}=\sqrt{\frac{40}{4}}=\sqrt{10}=3.16$

Standard 11
Physics

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