Figure shows two flasks connected to each other. volume of flask 1 is twice that of flask 2 . system

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12.Kinetic Theory of Gases

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Figure shows two flasks connected to each other. The volume of the flask $1$ is twice that of flask $2$. The system is filled with an ideal gas at temperature $100\,K$ and $200\,K$ respectively. If the mass of the gas in $1$ be $m$ then what is the mass of the gas in flask $2$

A

$m$

B

$m/2$

C

$m/4$

D

$m/8$

Solution

At equilibrium pressure in both the flasks must be same.

Using ideal gas equation;

$\frac{ n _1 R T_1}{V_1}=\frac{ n _2 R T_2}{V_2}$

$\frac{ m _1 \times 100 K }{2 V _2}=\frac{ m _2 \times 200 K }{ V _2}$

$m _2=\frac{ m }{4}$

Standard 11

Physics

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