Gujarati
Hindi
11.Thermodynamics
normal

A monoatomic gas is supplied heat $Q$ very slowly keeping the pressure constant. The work done by the gas will be

A

$\frac{2}{3}\,Q$

B

$\frac{3}{4}\,Q$

C

$\frac{2}{5}\,Q$

D

$\frac{3}{5}\,Q$

Solution

$\mathrm{dQ}=\mathrm{C}_{\mathrm{p}} \mathrm{dT}=\frac{5}{2} \mathrm{RdT}$

$\mathrm{dU}=\mathrm{C}_{\mathrm{v}} \mathrm{dT}=\frac{3}{2} \mathrm{RdT}$

$\mathrm{d} \mathrm{W}=\mathrm{RdT}$

$\mathrm{d} \mathrm{W}=\frac{2}{5} \mathrm{d} \mathrm{Q}$

Standard 11
Physics

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