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11.Thermodynamics
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A monoatomic gas is supplied heat $Q$ very slowly keeping the pressure constant. The work done by the gas will be
A
$\frac{2}{3}\,Q$
B
$\frac{3}{4}\,Q$
C
$\frac{2}{5}\,Q$
D
$\frac{3}{5}\,Q$
Solution
$\mathrm{dQ}=\mathrm{C}_{\mathrm{p}} \mathrm{dT}=\frac{5}{2} \mathrm{RdT}$
$\mathrm{dU}=\mathrm{C}_{\mathrm{v}} \mathrm{dT}=\frac{3}{2} \mathrm{RdT}$
$\mathrm{d} \mathrm{W}=\mathrm{RdT}$
$\mathrm{d} \mathrm{W}=\frac{2}{5} \mathrm{d} \mathrm{Q}$
Standard 11
Physics
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